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5x^2^x+3=5/4
We move all terms to the left:
5x^2^x+3-(5/4)=0
We add all the numbers together, and all the variables
5x^2^x+3-(+5/4)=0
We get rid of parentheses
5x^2^x+3-5/4=0
We multiply all the terms by the denominator
5x^2^x*4-5+3*4=0
We add all the numbers together, and all the variables
5x^2^x*4+7=0
Wy multiply elements
20x^2+7=0
a = 20; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·20·7
Δ = -560
Delta is less than zero, so there is no solution for the equation
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